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Perplex
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Integration
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Anti-Derivative Rules
Techniques of Integration
Anti-Derivative Rules
Integration

Anti-Derivative Rules

0 of 0 exercises completed

Anti-derivatives of sums and scalar multiples, using linearity together with standard forms such as ​∫xndx=n+1xn+1​+C,  ​∫sinxdx=−cosx+C,  ​∫cosxdx=sinx+C,  ​∫exdx=ex+C,  ​∫x1​dx=ln∣x∣+C, and the usual trig and inverse trig results.

Anti-Derivative of xⁿ, n∈ℚ
SL 5.10
​
∫xndx=n+1xn+1​+C,n=−1📖
​
Anti-Derivative of e^x
SL 5.10
​
∫exdx=ex+C📖
​
Anti-Derivative of sin and cos
SL 5.10

The integrals of ​sin​ and ​cos​ are

​
∫sinxdx ∫cosxdx​=−cosx+C📖 =sinx+C📖​
​
Anti-derivatives of sums and scalar multiples
SL 5.10

The anti-derivative of a sum is the sum of the anti-derivatives:

​
∫f(x)+g(x)dx=∫f(x)dx+∫g(x)dx
​


The anti-derivative of a scalar multiple (a constant that does not depend on the integrating variable) can pass through the integral:

​
∫kf(x)dx=k∫f(x)dx
​
Anti-Derivative of 1/x
SL 5.6
​
∫x1​dx=ln∣x∣+C📖
​


Why the absolute value?

​x1​​ is defined for ​x<0, but ​lnx​ is not. Specifically:

​
dxd​(ln(−x))=−x−1​=x1​,
​


So ​x1​​ is the derivative of ​lnx​ and of ​ln(−x).


However, we can simplify further. Recall the definition of the absolute value:

​
∣x∣={−xx<0xx>0​.
​

Hence, we have

​
dxd​(ln∣x∣)=x1​
​
​
⟹∫x1​dx=ln(∣x∣)+C.
​
Anti-Derivative leading to tan
AHL 5.15
​
∫sec2xdx=tanx+C
​
Anti-Derivative leading to sec, cosec, and cot
AHL 5.15
​
∫secxtanxdx−∫cosecxcotx−∫cosec2x​=secx+Cdx=cosecx+Cdx=cotx+C​
​
Anti-Derivatives leading to arccos, arcsin, or arctan
AHL 5.15
​
∫√a2−x2​−1​dx=arccos(ax​)+C📖
​


​
∫√a2−x2​1​dx=arcsin(ax​)+C📖
​


​
∫a2+x21​dx=a1​arctan(ax​)+C📖
​
Anti-Derivative of aˣ
AHL 5.15
​
∫axdx=lna1​ax+C📖
​

Nice work completing Anti-Derivative Rules, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!
/
Integration
/
Anti-Derivative Rules
Techniques of Integration
Anti-Derivative Rules
Integration

Anti-Derivative Rules

0 of 0 exercises completed

Anti-derivatives of sums and scalar multiples, using linearity together with standard forms such as ​∫xndx=n+1xn+1​+C,  ​∫sinxdx=−cosx+C,  ​∫cosxdx=sinx+C,  ​∫exdx=ex+C,  ​∫x1​dx=ln∣x∣+C, and the usual trig and inverse trig results.

Anti-Derivative of xⁿ, n∈ℚ
SL 5.10
​
∫xndx=n+1xn+1​+C,n=−1📖
​
Anti-Derivative of e^x
SL 5.10
​
∫exdx=ex+C📖
​
Anti-Derivative of sin and cos
SL 5.10

The integrals of ​sin​ and ​cos​ are

​
∫sinxdx ∫cosxdx​=−cosx+C📖 =sinx+C📖​
​
Anti-derivatives of sums and scalar multiples
SL 5.10

The anti-derivative of a sum is the sum of the anti-derivatives:

​
∫f(x)+g(x)dx=∫f(x)dx+∫g(x)dx
​


The anti-derivative of a scalar multiple (a constant that does not depend on the integrating variable) can pass through the integral:

​
∫kf(x)dx=k∫f(x)dx
​
Anti-Derivative of 1/x
SL 5.6
​
∫x1​dx=ln∣x∣+C📖
​


Why the absolute value?

​x1​​ is defined for ​x<0, but ​lnx​ is not. Specifically:

​
dxd​(ln(−x))=−x−1​=x1​,
​


So ​x1​​ is the derivative of ​lnx​ and of ​ln(−x).


However, we can simplify further. Recall the definition of the absolute value:

​
∣x∣={−xx<0xx>0​.
​

Hence, we have

​
dxd​(ln∣x∣)=x1​
​
​
⟹∫x1​dx=ln(∣x∣)+C.
​
Anti-Derivative leading to tan
AHL 5.15
​
∫sec2xdx=tanx+C
​
Anti-Derivative leading to sec, cosec, and cot
AHL 5.15
​
∫secxtanxdx−∫cosecxcotx−∫cosec2x​=secx+Cdx=cosecx+Cdx=cotx+C​
​
Anti-Derivatives leading to arccos, arcsin, or arctan
AHL 5.15
​
∫√a2−x2​−1​dx=arccos(ax​)+C📖
​


​
∫√a2−x2​1​dx=arcsin(ax​)+C📖
​


​
∫a2+x21​dx=a1​arctan(ax​)+C📖
​
Anti-Derivative of aˣ
AHL 5.15
​
∫axdx=lna1​ax+C📖
​

Nice work completing Anti-Derivative Rules, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!

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